mn giải giúp mình pt câu 5 với

`(x-23)/24 + (x-22)/25 = (x-21)/26 + (x-20)/27`

`⇒ ( (x-23)/24 + 1 ) + ( (x-22)/25 + 1 ) = ( (x-21)/26 + 1 ) + ( (x-20)/27 + 1 )`

`⇒ ( (x-23)/24 + 24/24 ) + ( (x-22)/25 + 25/25 ) = ( (x-21)/26 + 26/26 ) + ( (x-20)/27 + 27/27 )`

`⇒ (x-47)/24 + (x-47)/25 = (x-47)/26 + (x-47)/27`

`⇒ (x-47)/24 + (x-47)/25 - (x-47)/26 - (x-47)/27 = 0`

`⇒ (x-47)(1/24 + 1/25 - 1/26 - 1/27) = 0`

Do `1/24 + 1/25 - 1/26 - 1/27 \ne 0 `

`⇒ x - 47 = 0`

`⇒ x = 47`

Vậy `S = {47}`